• 设a1,a2,a3,a4,a5构成等比数列,若a2a5<0,则下列各式正确的是试题及答案-单选题-云返教育

    • 试题详情

      设a1,a2,a3,a4,a5构成等比数列,若a2a5<0,则下列各式正确的是         

      试题解答


      D
      设公比为q,由等比数列的通项公式可得a2a5=a1q?a1q4=a12?q5<0,
      ∴q<0;
      A、a
      1a3a4a5=a1?a1q2?a1q3?a1q4=a14q9<0,故错误;
      B、a
      1a2a4a5=a1?a1q?a1q3?a1q4=a14q8>0,故错误;
      C、a
      1a2a3a5=a1?a1q?a1q2?a1q4=a14q7<0,故错误;
      D、a
      1a2a3a4=a1?a1q?a1q2?a1q3=a14q6>0,故正确;
      故选D.
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