• 计算:(1)loga2+loga12 (a>0且a≠1);(2)lg20+log10025.试题及答案-解答题-云返教育

    • 试题详情

      计算:
      (1)log
      a2+loga
      1
      2
      (a>0且a≠1);
      (2)lg20+log
      10025.

      试题解答


      见解析
      解:(1)原式=loga2+loga
      1
      2
      =loga2-loga2=0,(a>0且a≠1);
      (2)原式=lg20+log
      10025=lg20+
      2
      2
      log105=lg20+lg5=lg100=2.
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