• (1)(6√m)5?m14√m?3√m?4√m= ;(2)log48= ;(3)lg√2+lg√5+log31= .试题及答案-填空题-云返教育

    • 试题详情

      (1)
      (
      6m
      )5?m
      1
      4
      m
      ?
      3m
      ?
      4m
      =         
      (2)log
      48=         
      (3)lg
      2
      +lg
      5
      +log31=         

      试题解答


      1:
      3
      2
      :
      1
      2

      解:(1)原式=
      m
      5
      6
      ?m
      1
      4
      m
      1
      2
      ?m
      1
      3
      ?m
      1
      4
      =m
      5
      6
      +
      1
      4
      -
      1
      2
      -
      1
      3
      -
      1
      4
      =m0=1;
      (2)原式=
      lg23
      lg22
      =
      3
      2

      (3)原式=lg
      2×5
      +0=
      1
      2
      lg10=
      1
      2

      故答案分别为1;
      3
      2
      1
      2
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