• 已知函数y=g(x)在[a,b]上单调递减,函数y=f(x)在[g(b),g(a)]上单调递减,证明:函数y=f(g(x))在[a,b]上单调递增.试题及答案-单选题-云返教育

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      已知函数y=g(x)在[a,b]上单调递减,函数y=f(x)在[g(b),g(a)]上单调递减,证明:函数y=f(g(x))在[a,b]上单调递增.

      试题解答


      见解析
      解:设t=g(x),
      任意设a≤x
      1<x2≤b,对应的函数值t1=g(x1),t2=g(x2),
      ∵函数y=g(x)在[a,b]上单调递减,
      ∴t
      1>t2
      ∵函数y=f(x)在[g(b),g(a)]上单调递减,
      ∴当t
      1>t2时,y1=f(t1)<y2=f(t2),
      即当a≤x
      1<x2≤b时,y1<y2
      ∴函数y=f(g(x))在[a,b]上单调递增.
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